How many grams of beryllium are needed to produce 36.0 g of hydrogen? (Assume an excess of water.)
Be(s) + 2H2 O(l) -> Be(OH)2 (aq) + H2 (g)a. 4.00 g
b. 36.0 g
c. 162 g
d. 324 g
Answer: C
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