One type of sunburn occurs on exposure to UV light of wavelength in the vicinity of 330 nm .What is the energy of a photon of this wavelength?
Answer:
Ephoton = (h x c) / Lambda
Ephoton = ((6.63x10^-34) x (3x10^8)) / (330x10^-9)
Ephoton = 6.03x10^-19 J