At 1470 K the value of Kp = 6.0 × 10−4 for the reaction below:
2CO(g) C (graphite) + CO2(g)
a. 0.0024 atm
b. 0.00030 atm
c. 0.0012 atm
d. 0.00060 atm
e. 0.00015 atm
Answer: a. 0.0024 atm
2CO(g) C (graphite) + CO2(g)
CO(g) initially at 2.00 atm is in contact with graphite until equilibrium is reached. What is the partial pressure of CO2(g) at equilibrium?
a. 0.0024 atm
b. 0.00030 atm
c. 0.0012 atm
d. 0.00060 atm
e. 0.00015 atm
Answer: a. 0.0024 atm