In a 1.0-liter container there are, at equilibrium, 0.10 mole H2, 0.20 mole N2, and 0.40 mole NH3. What is the value of Kc for this reaction at this temperature?

In a 1.0-liter container there are, at equilibrium, 0.10 mole H2, 0.20 mole N2, and 0.40 mole NH3. What is the value of Kc for this reaction at this temperature?

In a 1.0-liter container there are, at equilibrium, 0.10 mole H2, 0.20 mole N2, and 0.40 mole NH3. What is the value of Kc for this reaction at this temperature?



N2(g) + 3H2(g) 2NH3(g)

a. 0.0012
b. 20
c. 8.0 × 10^2
d. 0.050
e. 8.0


Answer: c. 8.0 × 10^2


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