The equilibrium constant for the formation of calcium carbonate from the ions in solution is
2.2 × 108 according to the reaction:
Ca^2+(aq) + CO3^2-(aq) <---> CaCO3(s)What is the value of the equilibrium constant for the reverse of this reaction?
a. the same, 2.2 × 108
b. −2.2 × 108
c. 2.2 × 10−8 x
d. 4.5 × 10−9 x
e. 4.5 × 109
Answer: 2.2 X 10^-8(wrong)