The value of Kp at 390.°C for the reversible reaction given below is 7.95 × 10−3. Calculate the value of Kp at 25°C. ΔH0 = 162 kJ/mol, R = 8.314 J/mol•K
A(g) + B(g) C(g)
a. 2.8 × 10^−2
b. 1.8 × 10^−18
c. 6.3 × 10^−12
d. 3.0 × 10^−14
e. 3.4 × 10^13
Answer: b. 1.8 × 10^−18