The reaction between lead ion and chloride ion is: Pb2+(aq) + 2Cl-(aq) PbCl2(s). If K = 2.57 x 107 for this reaction, what is the value for the equilibrium constant for the reaction: 2PbCl2(s) 2Pb2+(aq) + 4Cl-(aq)?
a. 3.89 x 10^-8
b. 6.60 x 10^14
c. 1.51 x 10^-15
d. 5.07 x 10^3
e. 1.97 x 10^-4
Answer: c. 1.51 x 10^-15