What would be the equilibrium concentration of PCl5(g) if 0.20 mole of PCl5(g) was placed in a 1.00-L container at this temperature? What would be the new equilibrium concentration of PCl5(g) if the volume were halved at this same temperature?

What would be the equilibrium concentration of PCl5(g) if 0.20 mole of PCl5(g) was placed in a 1.00-L container at this temperature? What would be the new equilibrium concentration of PCl5(g) if the volume were halved at this same temperature?

Given:
PCl5(g) PCl3(g) + Cl2(g) Kc = 0.040 at 450°C

What would be the equilibrium concentration of PCl5(g) if 0.20 mole of PCl5(g) was placed in a 1.00-L container at this temperature? What would be the new equilibrium concentration of PCl5(g) if the volume were halved at this same temperature?



a. 0.070 M; 0.29 M
b. 0.13 M; 0.29 M
c. 0.13 M; 0.11 M
d. 0.070 M; 0.13 M
e. 0.060 M; 0.14 M


Answer: b. 0.13 M; 0.29 M


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