What would be the equilibrium concentration of N2(g) if 0.12 mole of NO(g) was placed in a 1.00-L container at this temperature? What would be the new equilibrium concentration of N2(g) if the volume were halved at this same temperature?

What would be the equilibrium concentration of N2(g) if 0.12 mole of NO(g) was placed in a 1.00-L container at this temperature? What would be the new equilibrium concentration of N2(g) if the volume were halved at this same temperature?

Given:
N2(g) + O2(g) 2NO(g) Kc = 0.16

What would be the equilibrium concentration of N2(g) if 0.12 mole of NO(g) was placed in a 1.00-L container at this temperature? What would be the new equilibrium concentration of N2(g) if the volume were halved at this same temperature?



a. 0.050 M; 0.10 M
b. 0.050 M; 0.12 M
c. 0.070 M; 0.12 M
d. 0.10 M; 0.10 M
e. 0.50 M; 1.0 M


Answer: a. 0.050 M; 0.10 M


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